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Anonymous asked:
Determine whether the quadratic function f(x) =3X^square^ - 12x + 1 has a maximum or a minimum. Then find the maximum or the minimum of the value.
f(x) = 3x^2-12x+1
since a = 3 > 0, f has a minimum value at x = -b/2a
x = -(-12)/(2(3))
x = 2
f(2) = 3(2)^2 -12(2) + 1 = -11
So the minimum value of f is -11
